Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

if the quadratic formula is used to find the roots of the equation x^2-6x-19=0, what is the correct roots

Sagot :

D1eformetal
[tex] x^{2} -6x-19=0 \\ \\discriminant= b^{2}-4ac=> \\ 36-(-76)=76+36=112 \\ \\ -b- \sqrt{disc.}/2a=>6- \sqrt{112}/2 \\ =>6- 4\sqrt{7}/2 \\ =3- 2\sqrt{7} \\ \\ -b +\sqrt{disc}/2a=6+4 \sqrt{7} /2 \\ =3+ 2\sqrt{7} \\ \\ Solution\: set:(3- 2\sqrt{7} ,3+ 2\sqrt{7} ) \\ \\ \framebox[1.1\width]{Good Luck!!} \par[/tex]
konrad509
[tex]x^2-6x-19=0\\ x^2-6x+9-28=0\\ (x-3)^2=28\\ x-3=\sqrt{28} \vee x-3=-\sqrt{28}\\ x=3+2\sqrt7 \vee x=3-2\sqrt7[/tex]
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.