Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

if the quadratic formula is used to find the roots of the equation x^2-6x-19=0, what is the correct roots

Sagot :

D1eformetal
[tex] x^{2} -6x-19=0 \\ \\discriminant= b^{2}-4ac=> \\ 36-(-76)=76+36=112 \\ \\ -b- \sqrt{disc.}/2a=>6- \sqrt{112}/2 \\ =>6- 4\sqrt{7}/2 \\ =3- 2\sqrt{7} \\ \\ -b +\sqrt{disc}/2a=6+4 \sqrt{7} /2 \\ =3+ 2\sqrt{7} \\ \\ Solution\: set:(3- 2\sqrt{7} ,3+ 2\sqrt{7} ) \\ \\ \framebox[1.1\width]{Good Luck!!} \par[/tex]
konrad509
[tex]x^2-6x-19=0\\ x^2-6x+9-28=0\\ (x-3)^2=28\\ x-3=\sqrt{28} \vee x-3=-\sqrt{28}\\ x=3+2\sqrt7 \vee x=3-2\sqrt7[/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.