Answered

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What does k^2 -8k-20=0

Sagot :

dln
[tex]k^{2}-8k-20=0 \\ (k-10)(k+2)=0 \\ \\ k-10=0 \\ k=10 \\ \\ k+2=0 \\ k=-2 \\ \\ \boxed{k=-2\ and\ 10}[/tex]
Panoyin
k² - 8k - 20 = 0
k = -(-8) +/- √((-8)² - 4(1)(-20))
                       2(1)
k = 8 +/- √(64 + 80)
                 2
k = 8 +/- √(144)
              2
k = 8 +/- 12
            2
k = 8 + 12          k = 8 - 12
          2                        2
h = 20                k = -4
       2                        2
x = 10                k = -2
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