Ruya
Answered

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Hy! (√2+1)²+(3-√3)²-(√5+1)²=???
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Sagot :

konrad509
[tex](\sqrt2+1)^2+(3-\sqrt3)^2-(\sqrt5+1)^2=\\ 2+2\sqrt2+9-6\sqrt3+9-(5+2\sqrt5+1)=\\ 20+2\sqrt2-6\sqrt3-5-2\sqrt5-1=\\ 14+2\sqrt2-6\sqrt3-2\sqrt5[/tex]
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