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Marty ate 4/6 of his pizza and Luis ate 5/6 of his pizza. Marty ate more than Luis. How is that possible?

Sagot :

iGreen
If Luis had a smaller pizza with a diameter of 5 inches, and Marty ate a larger pizza with a diameter of 15 inches, Marty would eat more than Luis.

First, we can find the areas of the pizzas.

Luis's:

[tex]\sf~A=\pi\!\!~r^2[/tex]

Plug in what we know and simplify:

[tex]\sf~A=(3.14)(5)^2[/tex]

[tex]\sf~A=(3.14)(25)[/tex]

[tex]\sf~A=(78.5)[/tex]

Divide by 6 to see how big each slice is.

[tex]\sf78.5\div6\approx13.08[/tex]

Multiply by 5 to find out how much pizza Luis ate total:

[tex]\sf13.08\times5=65.4[/tex]

So Luis ate approximately 65.4 square inches of pizza.

Now let's find out how much Marty ate.

[tex]\sf~A=\pi\!\!~r^2[/tex]

Plug in what we know and simplify:

[tex]\sf~A=(3.14)(15)^2[/tex]

[tex]\sf~A=(3.14)(225)[/tex]

[tex]\sf~A=(706.5)[/tex]

Divide by 6 to see how big each slice is.

[tex]\sf78.5\div6=117.75[/tex]

Multiply by 5 to find out how much pizza Marty ate total:

[tex]\sf117.75\times5=588.75[/tex]

So Marty ate 588.75 square inches of pizza, which is more than what Luis ate, 65.4 square inches.
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