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how do i solve this? (1/3x-11)^(1/2)=5

Sagot :

[tex] (\frac{1}{3} x-11)^{ \frac{1}{2} }=5\\ ((\frac{1}{3} x-11)^{ \frac{1}{2} })^{2}=(5)^{2}\\ \frac{1}{3} x-11=25\\ \frac{1}{3} x=36\\x=108[/tex]
square both sides to get
(1/3x-11)=25
1/3x-11=25 then solve

why? because ^(1/2) means "take the square root". We need to "undo", or find the inverse so we square both sides.