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Sagot :
-- The x-intercept is the point where the line crosses the x-axis.
-- 'Y' is zero at every point on the x-axis.
-- So y=0 at the x-intercept.
You say that you have the equation of the line, and it's in
slope/intercept form ?
Y = mx + b
Great !
Just set y=0. Then you have mx + b = 0 .
Solve that for 'x' , and you have the x-intercept.
(It turns out to be x = - b/m . Always true, and a very handy formula
to remember if you can, and then you always have the x-intercept at
your fingertips whenever you need it.)
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