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the length of a rectangle is 50 feet less than its width. If the perimeter of the field is 840 feet, find the length of the field.

Sagot :

[tex]look\ at\ the\ picture\\\\2a+2(a-50)=840\\\\2a+2a-100=840\\\\4a-100=840\ \ \ /+100\\\\4a=940\ \ \ \ /:4\\\\a=235\ (ft)\\\\a-50=235-50=185\ (ft)\\\\Answer:lenght=185\ ft;\ width=235\ ft.[/tex]
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