Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
pythagorean theorem
c^2 = a^2 + b^2
c = 2x+1
a = 2x
b = x-1
plug in and get:
(2x+1)^2 = (2x)^2 + (x-1)^2
4x^2 + 4x + 1 = 4x^2 + x^2 - 2x + 1 [distributed]
4x^2 + 4x + 1 = 5x^2 - 2x + 1 [added like terms]
x^2 - 6x = 0 [subtracted 4x^2 and 4x and 1]
x(x-6)=0 [factored out x]
x can equal 0 or 6
0 would not make any sense physically
therefore x = 6
plug this back into the length of the ladder 2x+1
2(6)+1 = 12 + 1 = 13
therefore the ladder is 13 feet long
c^2 = a^2 + b^2
c = 2x+1
a = 2x
b = x-1
plug in and get:
(2x+1)^2 = (2x)^2 + (x-1)^2
4x^2 + 4x + 1 = 4x^2 + x^2 - 2x + 1 [distributed]
4x^2 + 4x + 1 = 5x^2 - 2x + 1 [added like terms]
x^2 - 6x = 0 [subtracted 4x^2 and 4x and 1]
x(x-6)=0 [factored out x]
x can equal 0 or 6
0 would not make any sense physically
therefore x = 6
plug this back into the length of the ladder 2x+1
2(6)+1 = 12 + 1 = 13
therefore the ladder is 13 feet long
so leangh of ladder=2x+1
bottom edgre=x-1
wall edge=2x
so therefor, since this is a right triangle, use pythagorean theorem
a^2+b^2=c^2
c=hypotonues=longest side
b and a=sides touching the right angle
so x-1 and 2x are a and b
2x+1=c
subsitute
(x-1)^2+(2x)^2=(2x+1)^2
x^2-2x+1+4x^2=4x^2+4x+1
add like terms
5x^2-2x+1=4x^2+4x+1
subtract 1 from both sdies
5x^2-2x=4x^2+4x
subtract 4x from both sdies
5x^2-6x=4x^2
subtract 4x^2 from both sides
x^2-6x =0
factor out the x using distributive property which is
ab+ac=a(b+c)
x^2-6x=x(x-6)
(x)(x-6)=0
if xy=0 then assume x and/or y=0
x=0
we remember that one of the side legnths is 2x and if x=0 then the side legnth=0 which is not possible, so we discard
x-6=0
add 6 to both sides
x=6
subsitute and solve
legnth of ladder=2x+1
x=6 subsitute
2(6)+1=12+1=13
legnth of ladder =13 feet
height=2x
2(6)=12
height=12 feet
base=x-1
6-1=5
legnth of ladder=13 feet
height=12 feet
base=5 feet
bottom edgre=x-1
wall edge=2x
so therefor, since this is a right triangle, use pythagorean theorem
a^2+b^2=c^2
c=hypotonues=longest side
b and a=sides touching the right angle
so x-1 and 2x are a and b
2x+1=c
subsitute
(x-1)^2+(2x)^2=(2x+1)^2
x^2-2x+1+4x^2=4x^2+4x+1
add like terms
5x^2-2x+1=4x^2+4x+1
subtract 1 from both sdies
5x^2-2x=4x^2+4x
subtract 4x from both sdies
5x^2-6x=4x^2
subtract 4x^2 from both sides
x^2-6x =0
factor out the x using distributive property which is
ab+ac=a(b+c)
x^2-6x=x(x-6)
(x)(x-6)=0
if xy=0 then assume x and/or y=0
x=0
we remember that one of the side legnths is 2x and if x=0 then the side legnth=0 which is not possible, so we discard
x-6=0
add 6 to both sides
x=6
subsitute and solve
legnth of ladder=2x+1
x=6 subsitute
2(6)+1=12+1=13
legnth of ladder =13 feet
height=2x
2(6)=12
height=12 feet
base=x-1
6-1=5
legnth of ladder=13 feet
height=12 feet
base=5 feet
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.