Answered

Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

PLEASEEE HELP. Solve x^3-7x^2+6x-42=0

Sagot :

eternal3fear
factor by grouping

x^2(x-7) + 6(x-7) = 0   [took x^2 out of the first two and a 6 out of the last two]
(x-7)(x^2+6) = 0     [moved (x-7) out to the front]
x = -i sqrt(6) , i sqrt(6) , 7

only one real solution of x = 7
[tex] x^{3} -7 x^{2} +6x-42=0[/tex]

[tex](x-7) [/tex] is a factor since it is a factor of -42 and 7 is a solution for f(x) to equal 0.

[tex](x-7)(a x^{2} +bx+c)=0[/tex]

[tex](x-7)( x^{2} +bx+6)=0[/tex]

[tex]-7 x^{2} +b x^{2} =-7 x^{2} [/tex]

[tex]-7+b=-7[/tex]

[tex]b=0[/tex]

[tex](x-7)( x^{2} +6)=0[/tex]

[tex]x-7=0[/tex]

[tex] x^{2} +6=0[/tex]

[tex]x=7[/tex] (only solution because you can't square root (-6))


Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.