Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

PLEASEEE HELP. Solve x^3-7x^2+6x-42=0

Sagot :

eternal3fear
factor by grouping

x^2(x-7) + 6(x-7) = 0   [took x^2 out of the first two and a 6 out of the last two]
(x-7)(x^2+6) = 0     [moved (x-7) out to the front]
x = -i sqrt(6) , i sqrt(6) , 7

only one real solution of x = 7
[tex] x^{3} -7 x^{2} +6x-42=0[/tex]

[tex](x-7) [/tex] is a factor since it is a factor of -42 and 7 is a solution for f(x) to equal 0.

[tex](x-7)(a x^{2} +bx+c)=0[/tex]

[tex](x-7)( x^{2} +bx+6)=0[/tex]

[tex]-7 x^{2} +b x^{2} =-7 x^{2} [/tex]

[tex]-7+b=-7[/tex]

[tex]b=0[/tex]

[tex](x-7)( x^{2} +6)=0[/tex]

[tex]x-7=0[/tex]

[tex] x^{2} +6=0[/tex]

[tex]x=7[/tex] (only solution because you can't square root (-6))


Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.