Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Simplify. (Polynomials)

1. (2cd^3)(-2c)(3c^d) =

2. (2x^2)(3x^6) - (4x^4)(2x^4) =

3. (6x^2)(3x^6) + (4x^4)(2x^4) =

4. (2ab^2)^2(-3a^2b^2) =

5. -6a^3(a^2-2a+1) =

6. -2xy(x^2-3xy+y^2) =

7. (a+b) (2a^2-ab+3b^2) =

(Please help asap!)


Sagot :

Since3122015
1. [tex](2cd^{3})(-2c)(3c^{d})=\\-12c^{d+2}d^{3}[/tex]

2. [tex](2x^{2})(3x^{6})-(4x^{4})(2x^{4})=\\6x^{8}-8x^{8}=\\-2x^{8}[/tex]

3. [tex](6x^{2})(3x^{6})+(4x^{4})(2x^{4})=\\18^{8}+8x^{8}=\\26x^{8}[/tex]

4. [tex](2ab^{2})^{2}(-3a^{2b^{2}})=\\4a^{2}b^{4}(-3a^{2b^{2}})=\\-12a^{2b^{2}+2}b^{4}[/tex]

5. [tex]-6a^{3}(a^{2}-2a+1)=\\-6a^{5}+12a^{4}-6a^{3}[/tex]

6. [tex]-2xy(x^{2}-3xy+y^{2})=\\-2x^{3}y+6x^{2}y^{2}-2xy^{3}[/tex]

7. [tex](a+b)(2a^{2}-ab+3b^{2})=\\2a^{3}-a^{2}b+3ab^{2}+2a^{2}b-ab^{2}+3b^{3}=\\2a^{3}+3b^{3}+a^{2}b+2ab^{2}[/tex]
Panoyin
1.[tex](2cd^{3})(-2c)(3cd) [/tex]
   [tex]-12c^{3}d^{4}[/tex]

2.[tex](2x^{2})(3x^{6}) - (4x^{4})(2x^{4})[/tex]
   [tex]6x^{8} - 8x^{8}[/tex]
   [tex]-2x^{8}[/tex]

3.[tex](6x^{2})(3x^{6}) + (4x^{4})(2x^{4})[/tex]
   [tex]18x^{8} + 8x^{8}[/tex]
   [tex]26x^{8}[/tex]

4.[tex](2ab^{2})^{2}(-3a^{2}b^{2})[/tex]
   [tex]((2ab^{2})(2ab^{2}))(-3a^{2}b^{2})[/tex]
   [tex](4a^{2}b^{4})(-3a^{2}b^{2})[/tex]
   [tex]-12a^{4}b^{6}[/tex]

5.[tex]-6a^{3}(a^{2} - 2a + 1)[/tex]
   [tex]-6a^{3}(a^{2}) + 6a^{3}(2a) - 6a^{3}(1)[/tex]
   [tex]-6a^{5} + 12a^{4} - 6a^{3}[/tex]

6.[tex]-2xy(x^{2} - 3xy + y^{2})[/tex]
   [tex]-2xy(x^{2}) + 2xy(3xy) - 2xy(y^{2})[/tex]
   [tex]-2x^{3}y + 6x^{2}y^{2} - 2xy^{3}[/tex]

7.[tex](a + b)(2a^{2} - ab + 3b^{2})[/tex]
   [tex](2a^{3} - a^{2}b + 3ab^{2} + 2a^{2}b - ab^{2} + 3b^{3})[/tex]
   [tex](2a^{3} - a^{2}b + 2a^{2}b + 3ab^{2} - ab^{2} + 3b^{3})[/tex]
   [tex]2a^{3} + a^{2}b + 2ab^{2} + 3b^{3}[/tex]
  
We hope this was helpful. Please come back whenever you need more information or answers to your queries. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.