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A quantity of gas weighing 7.1 g at 741 torr and 44 celius occupies 5.41 L. Find its molar mass.

Sagot :

1 atmosphere = 760 torr
R = 0.082
44 degrees Celsius = 317 degrees Kelvin

[tex]PV=NRT\\ \frac{744}{760}(5.41)=N(0.082)(317)\\ \frac{4025.04}{760}=25.994N\\\frac{4025.04}{19755.44}=N\\N=\frac{50313}{246943}\\0.203743[/tex]