Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
By Newton's law of gravitation
[tex]F= \frac{Gm_{1}m_{2}}{r^2} [/tex]
then for [tex]m_{1}=m_{2}=m[/tex]
[tex]r=sqrt{\frac{Gm^2}{F}}[/tex]
therefore
r=0.849m (3sf)
[tex]F= \frac{Gm_{1}m_{2}}{r^2} [/tex]
then for [tex]m_{1}=m_{2}=m[/tex]
[tex]r=sqrt{\frac{Gm^2}{F}}[/tex]
therefore
r=0.849m (3sf)
Answer:
d = 0.84 meters
Explanation:
It is given that,
Mass of two objects, [tex]m_1=m_2=2\times 10^2\ kg[/tex]
Gravitational force between them, [tex]F=3.7\times 10^{-6}\ N[/tex]
The force that exist between two objects is called gravitational force. Its expression is given by :
[tex]F=G\dfrac{m_1m_2}{d^2}[/tex]
Where
d is the distance between two masses
[tex]d=\sqrt{\dfrac{Gm^2}{F}}[/tex]
[tex]d=\sqrt{\dfrac{6.67\times 10^{-11}\times (2\times 10^2)^2}{3.7\times 10^{-6}}}[/tex]
d = 0.84 meters
So, the distance between two masses is 0.84 meters. Hence, this is the required solution.
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
