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Sagot :
i)
2=1*2
6=2*3
the first missing term is 3*4=12
20=4*5
the second missing term is 5*6=30
ii) Let a(n) be the nth term, then a(n+1)=(n+1)(n+2)=n^2+3n+2
iii) a(n+1)-a(n)=(n+1)(n+2)-n(n+1)=(n+1)(n+2-n)=2n+2 hence p=2,q=1
iv) Given question iii), we need to solve 2n+2=140 hence n=69
The two terms are 69 and 70 : (70*71)-(69*70)=140
2=1*2
6=2*3
the first missing term is 3*4=12
20=4*5
the second missing term is 5*6=30
ii) Let a(n) be the nth term, then a(n+1)=(n+1)(n+2)=n^2+3n+2
iii) a(n+1)-a(n)=(n+1)(n+2)-n(n+1)=(n+1)(n+2-n)=2n+2 hence p=2,q=1
iv) Given question iii), we need to solve 2n+2=140 hence n=69
The two terms are 69 and 70 : (70*71)-(69*70)=140
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