Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

2x+3y=12 how do I solve for x and y

Sagot :

favour14

2x+3y= 12

To solve for the x intercept, y=0

2x+3(0)= 12

2x= 12

Divide both sides by 2

2x/2x= 12/2x

X= 6

So:(6,0)

To solve for y intercept, x=0

2(0)+3y= 12

3y= 12

Divide both sides by 3

3y/3y= 12/3

Y= 4

So: (0,4)


Panoyin
2x + 3y = 12
2x - 2x + 3y = 12 - 2x
3y = 12 - 2x
 3          3
  y = 4 - 2/3x
2x + 3(4 - 2/3x) = 12
2x + 12 - 2x = 12
2x - 2x + 12 = 12
0x + 12 = 12
       -12   -12
        0x = 0
         0     0
         x = 0
2(0) + 3y = 12
0 + 3y = 12
-0          -0 
      3y = 12
       3      3
        y = 4
  (x, y) = (0, 4)
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.