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Sagot :
2x+3y= 12
To solve for the x intercept, y=0
2x+3(0)= 12
2x= 12
Divide both sides by 2
2x/2x= 12/2x
X= 6
So:(6,0)
To solve for y intercept, x=0
2(0)+3y= 12
3y= 12
Divide both sides by 3
3y/3y= 12/3
Y= 4
So: (0,4)
2x + 3y = 12
2x - 2x + 3y = 12 - 2x
3y = 12 - 2x
3 3
y = 4 - 2/3x
2x + 3(4 - 2/3x) = 12
2x + 12 - 2x = 12
2x - 2x + 12 = 12
0x + 12 = 12
-12 -12
0x = 0
0 0
x = 0
2(0) + 3y = 12
0 + 3y = 12
-0 -0
3y = 12
3 3
y = 4
(x, y) = (0, 4)
2x - 2x + 3y = 12 - 2x
3y = 12 - 2x
3 3
y = 4 - 2/3x
2x + 3(4 - 2/3x) = 12
2x + 12 - 2x = 12
2x - 2x + 12 = 12
0x + 12 = 12
-12 -12
0x = 0
0 0
x = 0
2(0) + 3y = 12
0 + 3y = 12
-0 -0
3y = 12
3 3
y = 4
(x, y) = (0, 4)
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