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how do i solve x^2-11x+14=0 using the quadratic formula

Sagot :

naǫ
[tex]x^2-11x+14=0 \\ \\ a=1 \\ b=-11 \\ c=14 \\ b^2-4ac=(-11)^2-4 \times 1 \times 14=121-56=65 \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}=\frac{-(-11) \pm \sqrt{65}}{2 \times 1}=\frac{11 \pm \sqrt{65}}{2} \\ \boxed{x=\frac{11 - \sqrt{65}}{2} \hbox{ or } x=\frac{11+\sqrt{65}}{2}}[/tex]
Panoyin
x² - 11x + 14 = 0
x = -(-11) +/- √((-11)² - 4(1)(14))
                        2(1)
x = 11 +/- √(121 - 56)
                   2
x = 11 +/- √(65)
               2
x = 11 +/- 8.062257748
                     2
x = 11 + 8.062257748      x = 11 - 8.062257748
                    2                                       2
x = 19.062257748            x = 2.937742252
                 2                                      2
x = 1.906225775              x = 1.468871126
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