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Quadratic Function help?

During the halftime of a basketball game, a sling shot launches T-shirts at the crowd. A T-shirt is launched with an initial upward velocity of 72 ft/s. The t-shirt is caught 35 ft above the court. The function y= -16t^2 + 72t +5 gives the T-shirts height h, in feet, after t seconds.

a. How long will it take the T-shirt to reach its maximum height?

b. What is the maximum height?

c. What is the range of the function that models the height of the T-shirt over time?

Thank you in Advance!

Sagot :

Dlesar
a) The T-shirt will be at its maximum height when the velocity is at zero, because its velocity will be at zero when it reaches the top of its arc.
You have the position function, y= -16t^2 + 72t + 5, so the velocity function is its derivative, v= -32t + 72.
Set that equal to zero, 0= -32t + 72, and solve for t.
0= -32t + 72
32t = 72
t = 9/4 or 2.25 seconds.

b) Plug what you found in part a) back into your position equation.
-16(2.25)^2 + 72(2.25) + 5 = -81 + 162 + 5 = 86 feet

c) The t-shirt's lowest point is 5 feet above the ground (that's the '+ 5' in the position equation) and its highest point is 86 feet, which you found in part b). So the range is [5,86]
raphealnwobi

The maximum height of the T-shirt is 86 feet at 2.25 seconds. The range of the function is [5, 85]

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Given the equation y = -16t² + 72t + 5

The maximum height is at y' = 0, hence:

y' = -32t + 72

-32t + 72 = 0

t = 2.25 seconds

Maximum height = -16(2.25)² + 72(2.25) + 5 = 86 feet

The maximum height of the T-shirt is 86 feet at 2.25 seconds. The range of the function is [5, 85]

Find out more on equation at: https://brainly.com/question/2972832

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