Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
[tex]P=\dfrac{\binom{4}{1}\binom{6}{2}}{\binom{6+4}{3}}=\dfrac{4*(6*5/2)}{10*9*8/(3*2)}=1/2[/tex]
The number of all possible 3-person groups
[tex]{10 \choose 3}=\dfrac{10!}{3!7!}=\dfrac{8\cdot9\cdot10}{6}=120[/tex]
The number of all possible groups consisting of 1 girl and 2 boys
[tex]4\cdot{6\choose 2}=4\cdot\dfrac{6!}{2!4!}=4\cdot\dfrac{5\cdot6}{2}=60[/tex]
The probability is [tex]\dfrac{60}{120}=\dfrac{1}{2}[/tex]
[tex]{10 \choose 3}=\dfrac{10!}{3!7!}=\dfrac{8\cdot9\cdot10}{6}=120[/tex]
The number of all possible groups consisting of 1 girl and 2 boys
[tex]4\cdot{6\choose 2}=4\cdot\dfrac{6!}{2!4!}=4\cdot\dfrac{5\cdot6}{2}=60[/tex]
The probability is [tex]\dfrac{60}{120}=\dfrac{1}{2}[/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.