Answered

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xsquaredminus 4xplus3=0

Sagot :

x² - 4x + 3 = 0
x² + (-4x) + 3 = 0
x = -(-4) +/- √((-4)² - 4(1)(3))
                     2(1)
x = 4 +/- √(16 - 12)
                 2
x = 4 +/- √(4)
            2
x = 4 +/- 2
           2
x = 4 + 2      x = 4 - 2
         2                  2
x = 6            x = 2
      2                  2
x = 3            x = 1
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