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how to solve 8-2[(5-3)^2 -1]= with steps please ^2 is for the power of 2

Sagot :

baonguyenq1999
=8-2[2^2-1]
=8-2(4-1)
=8-2(3)
=8-6
=2
Panoyin
8 - 2[(5 - 3)² - 1]
8 - 2[(2)² - 1]
8 - 2[4 - 1]
8 - 2[3]
8 - 6
2
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