Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

How many kilojoules of heat are required to heat 1.37kg of water from 21.3 to 89.5

Sagot :

q= ? kJ                  
m= 1.37 kg × [tex] \frac{1000 g}{1kg} [/tex] =1370 g
                      
c=4.18 J/g° C
ΔΤ= 89.5-21.3= 68.2˚C
? J = (1370 g) (4.18 J/g˚C) (68.2˚C)
q = 390,554 J× [tex] \frac{1kJ}{1000J} [/tex]
                 
                    q = 391 kJ
mickymike92

The quantity of Heat, Q, required to heat 1.37kg of water from 21.3 to 89.5 is 390.55 kJ.

What is quantity of Heat?

The quantity of Heat is the amount of heat energy added or removed from a substance.

  • Quantity of Heat = mass × specific heat capacity × temperature change

The quantity of Heat, Q, required to heat 1.37kg of water from 21.3 to 89.5 is calculated as follows:

  • Q = mcΔΤ

mass of water = 1.37 kg = 1370 g

specific heat capacity of water = 4.18 J/g° C

Temperature difference, ΔΤ= 89.5-21.3= 68.2˚C

Q = 1370 g × 4.18 J/g˚C × 68.2˚C

Q = 390,554.12

Q = 390.55 kJ

Therefore, the quantity of Heat, Q, required to heat 1.37kg of water from 21.3 to 89.5 is 390.55 kJ.

Learn more about quantity of Heat at: https://brainly.com/question/490326

#SPJ2

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.