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What is the acceleration of a 0.30 kilogram ball that is hit with a force of 25 N?

Sagot :

In order to calculate the acceleration on the ball, we use Newton's second law of motion, F = ma. Here, F is the resultant force, m is the mass of the body and a is the acceleration of the body. Therefore, a = F/m. a = 25 / 0.3 = 83 m/s^2.I hope that my answer is helpful! Let me know if you need something more :)
PBCHEM

Answer : Acceleration will be [tex] 83.3 m/s^{2} [/tex]

Explanation : For finding the acceleration one can use Newton's second law of motion and the formula is;

F = m . a

Where, F - Force;

m - mass of the object

a - acceleration.

We can rearrange the equation to find the acceleration;

a = F/m;

Given F - 25 N and m - 0.3 kg

Hence, a = 25 / 0.3 = [tex] 83.3 m/s^{2} [/tex]

Therefore, when the 0.3 kg ball is hit with a force of 25 N then the acceleration will be [tex] 83.3 m/s^{2} [/tex].