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Sagot :
First problem :
probability to draw a red paper : 42/(42+18)=7/10
In 110 tries one can thus expect to draw 7/10*110=77 red papers
Second problem :
Since for 150 trials (which will give the least error) we have got 135 yellow balls, we can expect twice as much in 300=150*2 trials, which makes 270 yellow balls.
probability to draw a red paper : 42/(42+18)=7/10
In 110 tries one can thus expect to draw 7/10*110=77 red papers
Second problem :
Since for 150 trials (which will give the least error) we have got 135 yellow balls, we can expect twice as much in 300=150*2 trials, which makes 270 yellow balls.
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