Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Let's say he's gonna use x grams of 90% gold alloy and y grams of 50% gold alloy.
The total percentage of gold in the mixture will thus be (x*0.9+y*0.5)/8=0.75 (=75%)
What is more x+y=8
The system is thus x+y=8, 0.9x+0.5y=8*0.75=6
From the first one we get y=8-x, which we insert in the second one : x(0.9-0.5)+0.5*8=4 hence x=(6-0.5*8)/(0.4)=5 and y=8-5=3
The answer is 5 grams of 90% gold and 3 grams of 50% gold
The total percentage of gold in the mixture will thus be (x*0.9+y*0.5)/8=0.75 (=75%)
What is more x+y=8
The system is thus x+y=8, 0.9x+0.5y=8*0.75=6
From the first one we get y=8-x, which we insert in the second one : x(0.9-0.5)+0.5*8=4 hence x=(6-0.5*8)/(0.4)=5 and y=8-5=3
The answer is 5 grams of 90% gold and 3 grams of 50% gold
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.