Answered

Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Solve the equation: sin^2x+2sinx*cosx-3cos^2x=0

Sagot :

sin²x - 2sinxcosx - 3cos²x = 0 | : cos²x
tg²x - 2tgx - 3 = 0
Substitution : TGX = a
a² - 2a - 3 = 0
by t . vieta : a₁ = 3
 a₂ = -1
inverse substitution :
TGA = 3
 x₁ = arctg3 + piN , n∈Z
TGA = -1
 x₂ = -π / 4 + piN , n∈Z      
On promežutke [ -π , π / 2 ] equation has two roots to -π / 4; arctg3
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.