Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
From the graph ...
-- Train-1 travels more than 15 feet in 3 seconds.
-- Train-2 travels less than 15 feet in 3 seconds.
So, if Train-3 travels exactly 15 feet in 3 seconds,
then Train-3 is faster than #2 but slower than #1 .
Answer:D. The third train is faster than Train 2 but slower than Train 1.
Step-by-step explanation:
Since, If the speed of one object is greater than that of other object then we can say that one object is faster than other object.
Here, the speed of third train = 15/3=5 feet/sec ( because speed = distance/time)
And, according to the given graph the speed of train 1= 30/5=6 feet/sec ( by taking the approximate value of x and y by the graph)
While, the speed of train 2= 20/5= 4 feet/sec
Thus, we can say that, Speed of train 1>Speed of train 3> Speed of train 2
Therefore, Only Option D is correct.
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.