kmann
Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Two carts collide on a level, friction-less track. Cart A has a mass of 200 g and is initially stationary. Cart B has a mass of 100 g and is initially moving with a velocity of +2.0 m/s. After the collision between the carts, cart B has a velocity of -0.5 m/s.

Calculate the velocity of cart A after the collision.
(Use conservation of momentum, KE is not conserved.)

Sagot :

convert 200 grams and 100 grams to 2kg and 1kg respectively 
momentum = mass x velocity 
momentum = 1 x 2 
initial momentum = 2 kg m/s
second scenario, cart b is moving -.5 m/s
momentum = mass x velocity
momentum = 1 x -.5
final momentum = -.5 kg m/s

momentum has to be the same in both scenarios so the 2 kg truck has to have a momentum of 2.5 kg m/s to push the total momentum of the second scenario to be 2 kg m/s like the first scenario

2.5 = 2 x velocity

velocity of cart a after the collision = 1.25 m/s

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.