Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

a gas had a volume of 50L and a temperature of 650k. if the temperature increased to 2600k, what would be the volume be?

Sagot :

Assuming it's a perfect gas, we have PV=nRT hence V and T are proportional. T increased by 2600/650=4 times hence the volume will be 4 times bigger, which is 200L
 Charles' Law:    V1V2         V2 = V1T2         V2 = (50L)(2600K) = 200L
                           T1    T2                   T1                         (650K)
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.