Westonci.ca is your go-to source for answers, with a community ready to provide accurate and timely information. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
[tex]f(x)=\sqrt{x^2-1},g(x)=\sqrt{x-1}[/tex]
Hence [tex]f(x)/g(x)=\sqrt{\frac{x^2-1}{x-1}}=\sqrt{\frac{(x+1)(x-1)}{x-1}}=\sqrt{x+1}[/tex]
Hence [tex]f(x)/g(x)=\sqrt{\frac{x^2-1}{x-1}}=\sqrt{\frac{(x+1)(x-1)}{x-1}}=\sqrt{x+1}[/tex]
[tex]f(x) = \sqrt{x^{2} - 1} [/tex]
[tex]g(x) = \sqrt{x - 1} [/tex]
[tex]\frac{f(x)}{g(x)} = \sqrt{\frac{x^{2} - 1}{x - 1}} [/tex]
[tex]\frac{f(x)}{g(x)} = \frac{\sqrt{x^{2} - 1}}{\sqrt{x - 1}} [/tex]
[tex]\frac{f(x)}{g(x)} = \frac{\sqrt{x^{2} + x - x - 1}}{\sqrt{x - 1}} [/tex]
[tex]\frac{f(x)}{g(x)} = \frac{\sqrt{(x - 1)(x + 1)}}{\sqrt{x - 1}} [/tex]
[tex] \frac{f(x)}{g(x)} = \sqrt{x + 1} [/tex]
[tex]g(x) = \sqrt{x - 1} [/tex]
[tex]\frac{f(x)}{g(x)} = \sqrt{\frac{x^{2} - 1}{x - 1}} [/tex]
[tex]\frac{f(x)}{g(x)} = \frac{\sqrt{x^{2} - 1}}{\sqrt{x - 1}} [/tex]
[tex]\frac{f(x)}{g(x)} = \frac{\sqrt{x^{2} + x - x - 1}}{\sqrt{x - 1}} [/tex]
[tex]\frac{f(x)}{g(x)} = \frac{\sqrt{(x - 1)(x + 1)}}{\sqrt{x - 1}} [/tex]
[tex] \frac{f(x)}{g(x)} = \sqrt{x + 1} [/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.