Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

what is the equation of the line that passes through (-9,12) and is perpendicular to the line whose equation is y=1/3x+6

Sagot :

apsweetangel9
d: 1/3x-y+6, A(-9, 12)
md=-b/a=1/1/3=3, md=slope d

d`: y-yA=md(x-xA)
     y-12=3(x+9)
     y-12=3x+27
=> d`: 3x-y+15=0
belcatya
y=kx+b
line is perpendicular y=1/3x+6⇒ k=-[tex] \frac{1}{ \frac{1}{3} } [/tex]=-3

 so line y=-3x+a
 this line that passes through (-9,12)⇔x=-9, y=12, so 12=-3(-9)+a
12=27+a
a=12-27
a=-15
y=-3x-15

P.s.picture to test solutions in the application


View image belcatya
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.