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Triangle ABC with vertices A(-2,-2) B(-3,1) C(1,1) is translated by
(x,y) ------> (x -1, y+3). THEN the image, triangle A'B'C', is translated by
(x,y) ------>(x + 4, y-1) resulting in A''B''C''.

FIND THE COORDINATES FOR THE VERTICES OF TRIANGLE A"B"C".
WRITE A RULE for 1 translation that maps triangle ABC to Triangle A"B"C".

PLEASE HELP!! I DO NOT UNDERSTAND THIS!! THANK YOU!

Sagot :

baonguyenq1999
Oh ok
so for example B(x,y)->B(-3,1) x=-3,y=1
it said to translate (x-1,y+3) go left 1 unit + go up 3 unit -> B'(-3-1,1+3)=B'(-4,4) then you do the same thing if it asks you to do it again

A'(-2-1,-2+3)->A'(-3,1)
B'(-4,4)
C'(1-1,1+3)->C'(0,4)

then translate again to get A"B"C" (x+4,y-1) go right 4 unit + go down 1 unit
A"(-3+4,1-1)->A"(1,0)
B"(-4+4,4-1)->B"(0,3)
C"(0+4,4-1)->C"(4,3)
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