Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A parallelogram with an equal base and height and an area greater than 64 square meters

Sagot :

Greenleafable
" Draw and then find the area" the base is equal to the height, and the area formula is A=BxH, so A=B²=H², if A>64m², so H>8 or B>8 (when drawing the figure)
calculista

Answer:

The base and the height of the parallelogram must be greater than [tex]8\ meters[/tex]

Step-by-step explanation:

we know that

The area of a parallelogram is equal to

[tex]A=bh[/tex]

where

b is the base

h is the height

In this problem we have

[tex]b=h[/tex] -----> given problem

so

[tex]A=b^{2}[/tex] ----> equation A

[tex]A> 64\ m^{2}[/tex] ------> inequality B

substitute equation A in the inequality B

[tex]b^{2}> 64\ m^{2}[/tex]

[tex]b> 8\ m[/tex]

The base and the height of the parallelogram must be greater than [tex]8\ meters[/tex]


Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.