Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A parallelogram with an equal base and height and an area greater than 64 square meters


Sagot :

" Draw and then find the area" the base is equal to the height, and the area formula is A=BxH, so A=B²=H², if A>64m², so H>8 or B>8 (when drawing the figure)

Answer:

The base and the height of the parallelogram must be greater than [tex]8\ meters[/tex]

Step-by-step explanation:

we know that

The area of a parallelogram is equal to

[tex]A=bh[/tex]

where

b is the base

h is the height

In this problem we have

[tex]b=h[/tex] -----> given problem

so

[tex]A=b^{2}[/tex] ----> equation A

[tex]A> 64\ m^{2}[/tex] ------> inequality B

substitute equation A in the inequality B

[tex]b^{2}> 64\ m^{2}[/tex]

[tex]b> 8\ m[/tex]

The base and the height of the parallelogram must be greater than [tex]8\ meters[/tex]


Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.