Answered

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Use f(x)=3x-1 and g(x)=7x to evaluate the following
(F+g)(6) (f-g)(-3) (fg)(5) (f/g)(0)

Sagot :

konrad509
[tex](f+g)(x)=3x-1+7x=10x-1\\ (f+g)(6)=10\cdot6-1=59\\\\ (f-g)(x)=3x-1-7x=-4x-1\\ (f-g)(x)=-4\cdot(-3)-1=11\\\\ (f\cdot g)(x)=(3x-1)\cdot7x=21x^2-7x\\ (f\cdot g)(x)=21\cdot5^2-7\cdot5=525-35=490\\\\ \left( \dfrac{f}{g}\right)(x)=\dfrac{3x-1}{7x}\\ 7x\not=0 \Rightarrow x\not=0 \Rightarrow \left( \dfrac{f}{g}\right)(0) \text{ doesn't exist} [/tex]
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