Answered

Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

What is a solution of x^2+6x=-5

Sagot :

konrad509
[tex]x^2+6x=-5\\ x^2+6x+5=0\\ x^2+x+5x+5=0\\ x(x+1)+5(x+1)=0\\ (x+5)(x+1)=0\\ x=-5 \vee x=-1[/tex]

Answer:

Solutions / zeroes of x² + 6x + 5 = 0 are -5 , -1

Step-by-step explanation:

Given: Quadratic equation, x² + 6x = -5

To find: Value of x or zeroes of equation

Rewrite the given equation in standard form,

x² + 6x + 5 = 0

now comparing it with standard form of quadratic equation

ax² + bx + c = 0

we get, a = 1 ,  b = 6 , c = 5

we first find discriminant, D to check if zeroes exit or not and nature of zeroes.

D = b² - 4ac

   = 6² - 4 × 1 × 5

   = 36 - 20

D = 16

Since, D > 0 i.e., positive

⇒ zeroes exist and they are real & distinct.

Now e can solve it by any method,

By middle term split method, we get

x² + 6x + 5 = 0

x² + 5x + x + 5 = 0

x ( x + 5) + ( x + 5 ) = 0

( x + 5 ) ( x + 1 ) = 0

now equating both factor with 0 we get,

x + 5 = 0     and   x + 1 = 0

x = -5 , -1

Therefore, Solutions / zeroes of x² + 6x + 5 = 0 are -5 , -1

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.