Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Join our platform to get reliable answers to your questions from a knowledgeable community of experts. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
[tex]\frac{x^2-8x+15}{x^2+x-12}=\frac{x^2-3x-5x+15}{x^2-3x+4x-12}=\frac{x(x-3)-5(x-3)}{x(x-3)+4(x-3)}=\frac{(x-5)(x-3)}{(x+4)(x-3)}= \\
=\boxed{\frac{x-5}{x+4}}, x \not= -4 \hbox{ and } x\not= 3[/tex]
[tex]\frac{x^{2} - 8x + 15}{x^{2} + x - 12} = \frac{x^{2} - 5x - 3x + 15}{x^{2} + 4x - 3x - 12} = \frac{(x - 3)(x - 5)}{(x - 3)(x + 4)} = \frac{x - 5}{x + 4} [/tex]
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.