At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
[tex]a_1=16;\ a_2=-4;\ a_3=1;\ a_4=-\frac{1}{4}\\\\q=a_2:a_1\\\\q=-4:16=-\frac{1}{4}\\\\a_n=a_1\cdot q^{n-1}\\\\a_n=16\cdot\left(-\frac{1}{4}\right)^{n-1}=16\cdot\left(-\frac{1}{4}\right)^n\cdot\left(-\frac{1}{4}\right)^{-1}\\\\=16\cdot\left(-\frac{1}{4}\right)^n\cdot(-4)=-64\cdot\left(-\frac{1}{4}\right)^n=(-4)^3\cdot\left(-\frac{1}{4}\right)^n=\left(-\frac{1}{4}\right)^{-3}\cdot\left(-\frac{1}{4}\right)^n\\\\=\left(-\frac{1}{4}\right)^{n-3}[/tex]
[tex]a_5=\left(-\frac{1}{4}\right)^{5-3}=\left(-\frac{1}{4}\right)^2=\frac{1}{16}\\\\a_6=\left(-\frac{1}{4}\right)^{6-3}=\left(-\frac{1}{4}\right)^3=-\frac{1}{64}\\\vdots[/tex]
[tex]a_5=\left(-\frac{1}{4}\right)^{5-3}=\left(-\frac{1}{4}\right)^2=\frac{1}{16}\\\\a_6=\left(-\frac{1}{4}\right)^{6-3}=\left(-\frac{1}{4}\right)^3=-\frac{1}{64}\\\vdots[/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.