Answered

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Rewrite the equation in vertex form: y=x^2-8x+13

Sagot :

[tex]vertex\ form:y=a(x-p)^2+q\\\\wher\ p=\frac{-b}{2a}\ and\ q=f(p)\\\\\\y=x^2-8x+13\\a=1;\ b=-8;\ c=13\\\\p=\frac{-(-8)}{2\cdot1}=\frac{8}{2}=4\\\\q=f(4)=4^2-8\cdot4+13=16-32+13=-3\\\\Answer:y=(x-4)^2-3[/tex]
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