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two people are independently choosing 3-topping pizza with 4 possible type of crust and 8 possible toppings.what is the probability that they choose the same exact crust and toppings combinations?

Sagot :

SchwarzschildRadius
So,

This is independent probability.

First, we have the two people.
[tex] \frac{1}{2} [/tex]

Then, we have 3 different toppings.
[tex] \frac{1}{2}* \frac{1}{3} = \frac{1}{6} [/tex]

Next, we have 4 possible types of crusts.
[tex] \frac{1}{6} * \frac{1}{4} = \frac{1}{24} [/tex]

Finally, we have the 8 possible toppings.
[tex] \frac{1}{24} * \frac{1}{8} = \frac{1}{192} [/tex]
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