Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Can someone PLEASE explain to me how the integral of 2cos^2(t)sin(t) dt =-(2/3)cos^3(t) ???

Sagot :

Hippalectryon
Do the change of variable [tex]u=\cos(t)\rightarrow du=-\sin(t)dt[/tex]

Then [tex]\int\2cos^2(t)\sin(t)dt=-2\int u^2du=-\frac{u^3}3=-\frac{2}3\cos^3(t)[/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.