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Sagot :
LiOH + HNO3 --> H2O + LiNO3
OH- + H+ --> H2O
OH - = 1.5M * .025L = .0375 mol
.0375mol/.04L = 0.9375M
Since it's at the equivalence point, OH- = H+ concentration
[HNO3] = 0.9375M
OH- + H+ --> H2O
OH - = 1.5M * .025L = .0375 mol
.0375mol/.04L = 0.9375M
Since it's at the equivalence point, OH- = H+ concentration
[HNO3] = 0.9375M
Answer:
Ca = 2.5M
Explanation:
Volume of Acid (Va) = 15ml
Concentration of acid (Ca) = ?
Volume of base (Vb) = 25
Concentration of base (Cb) = 1.50M
The balanced chemical equation is given as;
LiOH + HNO3 --> LiNO3 + H2O
The formular relaing the parameters is given as;
(CaVa) / (CbVb) = Na/Nb
Where Na = Number of moles of Acid = 1
Nb = Number of moles of Base = 1
Making Ca subject of interest;
Ca = (Na * Cb * Vb) / (Nb * Va)
Ca = (1 * 1.50 * 25) / (1 * 15)
Ca = 37.5 / 15
Ca = 2.5M
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