Answered

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if the sum of three consecutive even integers is 192, what is the first of the three integers?

Sagot :

daniel2019360
smallest:x-2
middle:x
biggest:x+2

smallest+middle=biggest=(x-2)+(x)+(x+2)=3x
3x=192->3x/3=192/3->x=64

smallest: 64-2=62
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