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what is the slope of the line 4x-8y-16=0 in simplest form?

Sagot :

[tex]The\ slope-intercept\ form:y=mx+b\\\\m-the\ slope\\----------------------\\\\4x-8y-16=0\ \ \ |add\ 8y\ to\ both\ sides\\\\4x-16=8y\ \ \ \ \ |divide\ both\ sides\ by\ 8\\\\\frac{4}{8}x-\frac{16}{8}=y\\\\y=\frac{1}{2}x-2\\\\Answer:\boxed{m=\frac{1}{2}}[/tex]
For ax+by+c=0 this equation; the slope is -a/b.

For 4x-8y-16 ; the slope is -4/-8 = 1/2