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5x+3y=-12 and 8x+7y=-6
solve the following systems of equations

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[tex]5x+3y=-12 \ \ \ |\times (- 7) \\ 8x+7y=-6 \ \ \ | \times 3\\ \\ -35x-21y=84 \\ \underline{24x+21y=-18 \ } \\ -35x+24x=84-18 \\ -11x=66 \ \ \ |\div (-11) \\ x=-6 \\ \\ 5x+3y=-12 \\ 5 \times (-6)+3y=-12 \\ -30+3y=-12 \ \ \ |+30 \\ 3y=18 \ \ \ |\div 3 \\ y=6 \\ \\ \boxed{(x,y)=(-6,6)} [/tex]
5x + 3y = -12 ⇒ 40x + 24y = -96
8x + 7y = -6   ⇒ 40x + 35y = -30
                                   -11y = -66
                                    -11     -11
                                        y = 6
                            5x + 3(6) = -12
                              5x + 18 = -12
                                     -18    -18
                                      5x = -30
                                       5       5
                                        x = -6
                                  (x, y) = (-6,6)