Answered

Explore Westonci.ca, the leading Q&A site where experts provide accurate and helpful answers to all your questions. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

We have a solution of C5H10O2 of concentration 4 M. Find out the volume we need to take from this solution to make a 250 mL solution of concentration 0.5 M.

Is my result right? I got 31.25 mL

Here's what I did:
M=moles solute / volume (L) solution (M=n/V)
First I calculate the moles of acid needed for a 0.5M, 0.25L solution.
n=M*V = 0.5*0.25 = 0.125 mol acid
Now knowing how many moles I need to take, I calculate the volume those moles occupy in the 4M solution.
V=n/M = 0.125/4 = 0.03125 L solution = 31.25 mL
So you need to take 31.25 mL of 4M acid solution and add 218.75 (250*31.25) of water to make a 0.5M, 250 mL solution.

Sagot :

Hippalectryon
You are right.

Here's an easier way to do it : 
We have an initial solution of concentration [tex]C[/tex].
We want to turn it into a [tex]V[/tex] mL solution of concentration [tex]C_1[/tex], and we want to know which volume [tex]V_1[/tex] of solution to take from the original to do that.
We know that [tex]C_1=C\frac{V_1}V[/tex] hence [tex]V_1=\frac{C_1}CV=\frac{0.5}4250=\frac{250}8=31.25 mL[/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.