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How do you work a least common denominator problem for each pair?

X+2=3/x


Sagot :

x + 2 = 3
   1       x
x(x + 2) = 3(1)
x(x) + x(2) = 3
x² + 2x = 3
x² + 2x - 3 = 0
x = -2 +/- √(2² - 4(1)(-3))
                   2(1)
x = -2 +/- √(4 + 12)
                  2
x = -2 +/- √(16)
               2
x = -2 +/- 4
            2
x = -1 + 2
x = -1 + 2      x = -1 - 2
x = 1             x = -3