Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Y=-2(x-1)^2+8 how do I factor this parabola? I need to find the zeros, vertex, and axis of symmetry

Sagot :

Panoyin
y = -2(x - 1)² + 8
y = -2((x - 1)(x - 1)) + 8
y = -2(x² - x - x + 1) + 8
y = -2(x² - 2x + 1) + 8
y = -2(x²) + 2(2x) - 2(1) + 8
y = -2x² + 4x - 2 + 8
y = 2x² + 4x + 6
2x² + 4x + 6 = 0
x = -4 +/- √(4² - 4(2)(6))
                   2(2)
x = -4 +/- √(16 - 48)
                  4
x = -4 +/- √(-32)
               4
x = -4 +/- 5.6568i
                4
x = -4 +/- 1.4142i
x = -4 + 1.4142i                x = -4 - 1.4142
y = -2x² + 4x + 6
y = -2(-4 + 1.4142i)² + 4(-4 + 1.4142i) + 6
y = -2((-4 + 1.4142i)(-4 + 4.4142i) - 16 + 5.6568i + 6
y = -2(16 - 5.6568i - 5.6568i + 1.99996164i²) - 16 + 5.6568i + 6
y = -2(16 - 11.3136i + 1.9996164) - 16 + 5.6568i + 6
y = -32 + 22.6272i - 3.99992328 - 16 + 5.6568i + 6
y = -32 - 3.99992328 - 16 + 6 + 22.6272i + 5.6568i
y = -35.99992328 - 16 + 6 + 28.284i
y = -51.99992328 + 6 + 28.284i
y = -45.99992328 + 28.284i
(x, y) = (-4 + 1.4142i, -45.99992328 + 28.284i)
y = -2x² + 4x + 6
y = -2(-4 - 1.4142i)² + 4(-4 - 1.4142i) + 6
y = -2((-4 - 1.4142i)(-4 - 1.4142i)) - 16 - 5.6568i + 6
y = -2(16 + 5.6568i + 5.6568i + 1.99996164i²) - 16 - 5.6568i + 6
y = -2(16 + 11.3136i + 1.99996164) - 16 - 5.6568i + 6
y = -32 - 22.6272i - 3.99992328 - 16 - 5.6568i + 6
y = -32 - 3.99992328 - 16 + 6 - 22.6272i - 5.6568i
y = -35.99992328 - 16 + 6 - 28.284i
y = -51.99992328 + 6 - 28.284i
y = -45.99992328 - 28.284i
(x, y) = (-4 - 1.4142i, -45.99992328 - 28.284i)
zeros: -4 + 1.4142i or -4 - 1.4142i
vertex: (-4 + 1.4142i, -45.99992328 + 28.284i) and (-4 - 1.4142i, -45.99992328 - 28.284i)
axis of symmetry: 0 + 2.8284i
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.