DenominatorHater
Answered

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What is the surface area of the prism?



A.
164 yd2

B.
204 yd2

C.
240 yd2

D.
300 yd2

What Is The Surface Area Of The Prism A 164 Yd2 B 204 Yd2 C 240 Yd2 D 300 Yd2 class=

Sagot :

[tex]The\ surface\ area:A_s=2B+(S_1+S_2+S_3)\cdot H\\B=\frac{12\cdot5}{2}=\frac{60}{2}=\boxed{30\ (yd^2)}\\\\S_1=5yd;\ S_2=12yd;\ S_3=13yd;\ h=8yd\\\\therefore\\\\A_s=2\cdot30+(5+12+13)\cdot8=60+30\cdot8=60+240=\boxed{300\ (yd^2)}[/tex][tex]Volume\ of\ the\ prism:V=B\cdot H\\\\B\ (base)\ it's\ a\ right\ triangle:B=\frac{12\cdot5}{2}=\frac{60}{2}=\boxed{30\ (yd^2)}\\\\H=8yd\\\\therefore\\\\V=30\cdot8=\boxed{240\ (yd^2)}\leftarrow\boxed{C}[/tex]
codymilner
Dan's calculations are correct, but we're not solving for the volume of the prism, we're solving for the surface area. To calculate that, we take the surface area of the two triangles on the ends, (already shown to be 30 yds2 each, so when counting both comes to 60yds), plus the surface area of the side that is 8 by 13, the side that is 8 by 12, and the side that is 8 by 5. 8x5=40, 8x12=96, 8x13=104. 40+96+104+(previously determined)60 = 300. So the surface area is 300 yds2.
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