Answered

Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

in the equation y =2x^2-5x-18 which is the value of x when y=0

Sagot :

Panoyin
y = 2x² - 5x - 18
2x - 5x - 18 = 0
x = -(-5) +/- √((-5)² - 4(2)(-18))
                        2(2)
x = 5 +/- √(25 + 144)
                   4
x = 5 +/- √(169)
              4
x = 5 +/- 13
           4
x = 5 + 13       x = 5 - 13
          4                     4
x = 18             x = -8
       4                     4
x = 4 1/2         x = -2
-----------------------------------------------------------------------------------------------
y = 2x² - 5x - 18
y = 2(4 1/2)² - 5(4 1/2) - 18
y = 2(20 1/4) - 22 1/2 - 18
y = 40 1/2 - 22 1/2 - 18
y = 18 - 18
y = 0
(x, y) = (4 1/2, 0)
or
y = 2x² - 5x - 18
y = 2(2)² - 5(2) - 18
y = 2(4) - 10 - 18
y = 8 - 10 - 8
y = -2 - 8
y = -10
(x, y) = (2, -10)
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.