GIVEN: ABCD is a rectangle
Diagonals AC and BD intersect at E

PROVE:Triangle AEB is isosceles

Question

27-03-2015
Mathematics

Answered

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GIVEN: ABCD is a rectangle
Diagonals AC and BD intersect at E

PROVE:Triangle AEB is isosceles

Sagot :

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techface techface · Answer 1 · 2015-03-27T20:23:59-04:00

techface techface

27-03-2015

Because both diagonals AC and BD are the same length, that means that where they intersect at is the same length(i.e AE and BE). Since those are the same, that means that this triangle should be an isosceles triangle, with at least 2 sides having the same length.

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GIVEN: ABCD is a rectangle Diagonals AC and BD intersect at E PROVE:Triangle AEB is isosceles

Sagot :

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GIVEN: ABCD is a rectangle
Diagonals AC and BD intersect at E

PROVE:Triangle AEB is isosceles