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Sagot :
The scale has two sides:
The Left Hand Side (LHS) and the Right Hand Side (RHS).
Let the weight of the sphere be represented as s
Let the weight of the cube be represented as c
Let the LHS have the 5 spheres and 1 cube, represented as = (5s + 1c)
Let the RHS have the 2 spheres and 3 cubes, represented as = (2s + 3c)
If the cube c, weighs 150 gram, c = 150g
Since the scale is balanced, therefore the weights on the LHS would be equal to the weights on the RHS.
Therefore: (5s + 1c) = (2s + 3c), c = 150.
(5s + 1*150) = (2s + 3*150)
(5s + 150) = (2s + 450) collect like terms.
5s - 2s = 450 - 150
3s = 300 Divide both sides by 3
s = 300/3
s = 100
Therefore the sphere weighs 100 gram each.
The Left Hand Side (LHS) and the Right Hand Side (RHS).
Let the weight of the sphere be represented as s
Let the weight of the cube be represented as c
Let the LHS have the 5 spheres and 1 cube, represented as = (5s + 1c)
Let the RHS have the 2 spheres and 3 cubes, represented as = (2s + 3c)
If the cube c, weighs 150 gram, c = 150g
Since the scale is balanced, therefore the weights on the LHS would be equal to the weights on the RHS.
Therefore: (5s + 1c) = (2s + 3c), c = 150.
(5s + 1*150) = (2s + 3*150)
(5s + 150) = (2s + 450) collect like terms.
5s - 2s = 450 - 150
3s = 300 Divide both sides by 3
s = 300/3
s = 100
Therefore the sphere weighs 100 gram each.
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