Answered

Explore Westonci.ca, the premier Q&A site that helps you find precise answers to your questions, no matter the topic. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

10. A quantity of a gas has an absolute pressure of 400 kPa and an absolute temperature of 110 degrees kelvin. When the temperature of the gas is raised to 235 degrees kelvin, what is the new pressure of the gas? (Assume that there''s no change in volume.)
A. 1.702 kPa
B. 3.636 kPa
C. 854.46 kPa
D. 510 kPa

Sagot :

Since3122015
Given that N and V are constants:

[tex]P=\frac{NRT}{V}\\(400)=(8.31)(110)\frac{N}{V}\\400=914.59\frac{N}{V}\\\frac{400}{914.59}=\frac{N}{V}\\\\P=(8.31)(235)\frac{N}{V}\\P=(1953.90)\frac{400}{914.59}\\P=854.55\\854.55=about~854.46[/tex]

C. 854.46 kPa

Answer : (C) 854.46 KPa.

Solution : Given,

Initial pressure = 400 KPa

Initial temperature = 110 K

Final temperature = 235 K

According to the Gay-Lussac's law, the absolute pressure is directly proportional to the absolute temperature at constant volume of an ideal gas.

P  ∝  T

Formula used :  

[tex]\frac{P_{1}}{P_{2}}=\frac{T_{1}}{T_{2}}[/tex]

where,

[tex]P_{1}[/tex] = initial pressure

[tex]P_{2}[/tex] = final pressure

[tex]T_{1}[/tex] = initial temperature

[tex]T_{2}[/tex] = final temperature

Now put all the values in above formula, we get

[tex]\frac{400}{P_{2}}=\frac{110}{235}[/tex]

By rearranging the terms, we get the value of new/final pressure.

[tex]P_{2}[/tex] = 854.5454 KPa [tex]\approx[/tex] 854.55 KPa

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.